ASVAB Arithmetic Reasoning Practice Test 114326 Results

Your Results Global Average
Questions 5 5
Correct 0 3.35
Score 0% 67%

Review

1

4! = ?

85% Answer Correctly

5 x 4 x 3 x 2 x 1

4 x 3 x 2 x 1

3 x 2 x 1

4 x 3


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


2

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

least common multiple

greatest common multiple

greatest common factor

absolute value


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


3

Solve 2 + (3 + 4) ÷ 3 x 4 - 42

53% Answer Correctly
-4\(\frac{2}{3}\)
1\(\frac{1}{6}\)
\(\frac{2}{5}\)
1\(\frac{1}{8}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (3 + 4) ÷ 3 x 4 - 42
P: 2 + (7) ÷ 3 x 4 - 42
E: 2 + 7 ÷ 3 x 4 - 16
MD: 2 + \( \frac{7}{3} \) x 4 - 16
MD: 2 + \( \frac{28}{3} \) - 16
AS: \( \frac{6}{3} \) + \( \frac{28}{3} \) - 16
AS: \( \frac{34}{3} \) - 16
AS: \( \frac{34 - 48}{3} \)
\( \frac{-14}{3} \)
-4\(\frac{2}{3}\)


4

What is \( \sqrt{\frac{4}{36}} \)?

70% Answer Correctly
1
\(\frac{1}{3}\)
\(\frac{5}{8}\)
\(\frac{8}{9}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{4}{36}} \)
\( \frac{\sqrt{4}}{\sqrt{36}} \)
\( \frac{\sqrt{2^2}}{\sqrt{6^2}} \)
\(\frac{1}{3}\)


5

What is \( \frac{8}{2} \) - \( \frac{3}{6} \)?

61% Answer Correctly
2 \( \frac{1}{6} \)
3\(\frac{1}{2}\)
1 \( \frac{3}{6} \)
1 \( \frac{7}{15} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 3}{2 x 3} \) - \( \frac{3 x 1}{6 x 1} \)

\( \frac{24}{6} \) - \( \frac{3}{6} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{24 - 3}{6} \) = \( \frac{21}{6} \) = 3\(\frac{1}{2}\)