| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.35 |
| Score | 0% | 67% |
4! = ?
5 x 4 x 3 x 2 x 1 |
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4 x 3 x 2 x 1 |
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3 x 2 x 1 |
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4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
The __________ is the greatest factor that divides two integers.
least common multiple |
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greatest common multiple |
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greatest common factor |
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absolute value |
The greatest common factor (GCF) is the greatest factor that divides two integers.
Solve 2 + (3 + 4) ÷ 3 x 4 - 42
| -4\(\frac{2}{3}\) | |
| 1\(\frac{1}{6}\) | |
| \(\frac{2}{5}\) | |
| 1\(\frac{1}{8}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (3 + 4) ÷ 3 x 4 - 42
P: 2 + (7) ÷ 3 x 4 - 42
E: 2 + 7 ÷ 3 x 4 - 16
MD: 2 + \( \frac{7}{3} \) x 4 - 16
MD: 2 + \( \frac{28}{3} \) - 16
AS: \( \frac{6}{3} \) + \( \frac{28}{3} \) - 16
AS: \( \frac{34}{3} \) - 16
AS: \( \frac{34 - 48}{3} \)
\( \frac{-14}{3} \)
-4\(\frac{2}{3}\)
What is \( \sqrt{\frac{4}{36}} \)?
| 1 | |
| \(\frac{1}{3}\) | |
| \(\frac{5}{8}\) | |
| \(\frac{8}{9}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{4}{36}} \)
\( \frac{\sqrt{4}}{\sqrt{36}} \)
\( \frac{\sqrt{2^2}}{\sqrt{6^2}} \)
\(\frac{1}{3}\)
What is \( \frac{8}{2} \) - \( \frac{3}{6} \)?
| 2 \( \frac{1}{6} \) | |
| 3\(\frac{1}{2}\) | |
| 1 \( \frac{3}{6} \) | |
| 1 \( \frac{7}{15} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 3}{2 x 3} \) - \( \frac{3 x 1}{6 x 1} \)
\( \frac{24}{6} \) - \( \frac{3}{6} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{24 - 3}{6} \) = \( \frac{21}{6} \) = 3\(\frac{1}{2}\)