ASVAB Arithmetic Reasoning Practice Test 123958 Results

Your Results Global Average
Questions 5 5
Correct 0 3.12
Score 0% 62%

Review

1

What is \( \sqrt{\frac{49}{36}} \)?

70% Answer Correctly
1\(\frac{1}{6}\)
1\(\frac{1}{2}\)
\(\frac{3}{5}\)
\(\frac{2}{3}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{36}} \)
\( \frac{\sqrt{49}}{\sqrt{36}} \)
\( \frac{\sqrt{7^2}}{\sqrt{6^2}} \)
\( \frac{7}{6} \)
1\(\frac{1}{6}\)


2

April scored 76% on her final exam. If each question was worth 3 points and there were 210 possible points on the exam, how many questions did April answer correctly?

57% Answer Correctly
60
53
67
43

Solution

April scored 76% on the test meaning she earned 76% of the possible points on the test. There were 210 possible points on the test so she earned 210 x 0.76 = 159 points. Each question is worth 3 points so she got \( \frac{159}{3} \) = 53 questions right.


3

What is the least common multiple of 6 and 14?

73% Answer Correctly
33
9
84
42

Solution

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 14 are [14, 28, 42, 56, 70, 84, 98]. The first few multiples they share are [42, 84] making 42 the smallest multiple 6 and 14 have in common.


4

Convert c-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{-1}{-3c} \)
\( \frac{1}{c^3} \)
\( \frac{-3}{c} \)
\( \frac{-3}{-c} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


5

On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
12
22
13
24

Solution
If the guard hits 50% of his shots and takes 10 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{50}{100} \) = \( \frac{50 x 10}{100} \) = \( \frac{500}{100} \) = 5 shots

The center makes 40% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{5}{\frac{40}{100}} \) = 5 x \( \frac{100}{40} \) = \( \frac{5 x 100}{40} \) = \( \frac{500}{40} \) = 13 shots

to make the same number of shots as the guard and thus score the same number of points.