ASVAB Arithmetic Reasoning Practice Test 197710 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

least common multiple

absolute value

greatest common factor

greatest common multiple


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


2

Which of the following is an improper fraction?

71% Answer Correctly

\({2 \over 5} \)

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


3

If the ratio of home fans to visiting fans in a crowd is 2:1 and all 44,000 seats in a stadium are filled, how many home fans are in attendance?

49% Answer Correctly
25,500
25,000
39,200
29,333

Solution

A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:

44,000 fans x \( \frac{2}{3} \) = \( \frac{88000}{3} \) = 29,333 fans.


4

The total water usage for a city is 20,000 gallons each day. Of that total, 13% is for personal use and 40% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
13,950
1,800
5,400
2,200

Solution

40% of the water consumption is industrial use and 13% is personal use so (40% - 13%) = 27% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{27}{100} \) x 20,000 gallons = 5,400 gallons.


5

What is \( \frac{4}{7} \) ÷ \( \frac{1}{8} \)?

68% Answer Correctly
4\(\frac{4}{7}\)
\(\frac{9}{49}\)
\(\frac{1}{12}\)
\(\frac{9}{40}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{7} \) ÷ \( \frac{1}{8} \) = \( \frac{4}{7} \) x \( \frac{8}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{7} \) x \( \frac{8}{1} \) = \( \frac{4 x 8}{7 x 1} \) = \( \frac{32}{7} \) = 4\(\frac{4}{7}\)