| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.91 |
| Score | 0% | 58% |
Which of the following is a mixed number?
\({7 \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({a \over 5} \) |
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\({5 \over 7} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Cooks are needed to prepare for a large party. Each cook can bake either 3 large cakes or 18 small cakes per hour. The kitchen is available for 4 hours and 28 large cakes and 360 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 9 | |
| 7 | |
| 8 | |
| 13 |
If a single cook can bake 3 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 3 x 4 = 12 large cakes during that time. 28 large cakes are needed for the party so \( \frac{28}{12} \) = 2\(\frac{1}{3}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 18 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 18 x 4 = 72 small cakes during that time. 360 small cakes are needed for the party so \( \frac{360}{72} \) = 5 cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 5 = 8 cooks.
Solve 3 + (4 + 5) ÷ 2 x 4 - 52
| -4 | |
| \(\frac{1}{3}\) | |
| \(\frac{3}{4}\) | |
| \(\frac{7}{9}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (4 + 5) ÷ 2 x 4 - 52
P: 3 + (9) ÷ 2 x 4 - 52
E: 3 + 9 ÷ 2 x 4 - 25
MD: 3 + \( \frac{9}{2} \) x 4 - 25
MD: 3 + \( \frac{36}{2} \) - 25
AS: \( \frac{6}{2} \) + \( \frac{36}{2} \) - 25
AS: \( \frac{42}{2} \) - 25
AS: \( \frac{42 - 50}{2} \)
\( \frac{-8}{2} \)
-4
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Roger buys two shirts, each with a regular price of $14, how much will he pay for both shirts?
| $16.10 | |
| $21.00 | |
| $15.40 | |
| $7.00 |
By buying two shirts, Roger will save $14 x \( \frac{50}{100} \) = \( \frac{$14 x 50}{100} \) = \( \frac{$700}{100} \) = $7.00 on the second shirt.
So, his total cost will be
$14.00 + ($14.00 - $7.00)
$14.00 + $7.00
$21.00
If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 15 | |
| 18 | |
| 16 | |
| 13 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 24 - 9 = 15 new staff for the busy season.