| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
A bread recipe calls for 2\(\frac{7}{8}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?
| 2\(\frac{3}{4}\) cups | |
| 1\(\frac{1}{2}\) cups | |
| 1 cups | |
| 1\(\frac{5}{8}\) cups |
The amount of flour you need is (2\(\frac{7}{8}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{23}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{13}{8} \) cups
1\(\frac{5}{8}\) cups
If all of a roofing company's 16 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 16 | |
| 1 | |
| 12 | |
| 4 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 7 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 7 x 4 = 28 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 28 - 16 = 12 new staff for the busy season.
10 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?
| 8 | |
| 4 | |
| 3 | |
| 1 |
There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 10 people needing transportation leaving 10 - 6 = 4 who will have to find other transportation.
If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?
| 18 m2 | |
| 8 m2 | |
| 98 m2 | |
| 32 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.
Putting these two equations together and solving for width (w):
2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2
Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2
4! = ?
4 x 3 x 2 x 1 |
|
4 x 3 |
|
5 x 4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.