The factors of a number are all positive integers that divide evenly into the number. The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{7 x 5}{6 x 5} \) - \( \frac{4 x 3}{10 x 3} \)

\( \frac{35}{30} \) - \( \frac{12}{30} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{35 - 12}{30} \) = \( \frac{23}{30} \) = \(\frac{23}{30}\)

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

4x² - 9x²
(4 - 9)x²
-5x²

A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:

43,000 fans x \( \frac{2}{3} \) = \( \frac{86000}{3} \) = 28,667 fans.

If the tiger has consumed 104 pounds of food in 8 days that's \( \frac{104}{8} \) = 13 pounds of food per day. The tiger needs to consume 182 - 104 = 78 more pounds of food to reach 182 pounds total. At 13 pounds of food per day that's \( \frac{78}{13} \) = 6 more days.