| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
commutative |
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associative |
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distributive |
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PEDMAS |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
18 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?
| 5 | |
| 3 | |
| 1 | |
| 7 |
There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 18 people needing transportation leaving 18 - 15 = 3 who will have to find other transportation.
How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?
| 8 | |
| 3 | |
| 4 | |
| 2 |
To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4
Solve 5 + (2 + 4) ÷ 3 x 5 - 32
| 1\(\frac{1}{5}\) | |
| 6 | |
| 2 | |
| 1\(\frac{1}{3}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (2 + 4) ÷ 3 x 5 - 32
P: 5 + (6) ÷ 3 x 5 - 32
E: 5 + 6 ÷ 3 x 5 - 9
MD: 5 + \( \frac{6}{3} \) x 5 - 9
MD: 5 + \( \frac{30}{3} \) - 9
AS: \( \frac{15}{3} \) + \( \frac{30}{3} \) - 9
AS: \( \frac{45}{3} \) - 9
AS: \( \frac{45 - 27}{3} \)
\( \frac{18}{3} \)
6
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 34 | |
| 55 | |
| 30 | |
| 28 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{45}{100} \) = \( \frac{45 x 25}{100} \) = \( \frac{1125}{100} \) = 11 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{11}{\frac{40}{100}} \) = 11 x \( \frac{100}{40} \) = \( \frac{11 x 100}{40} \) = \( \frac{1100}{40} \) = 28 shots
to make the same number of shots as the guard and thus score the same number of points.