ASVAB Arithmetic Reasoning Practice Test 558198 Results

Your Results Global Average
Questions 5 5
Correct 0 3.55
Score 0% 71%

Review

1

21 members of a bridal party need transported to a wedding reception but there are only 4 4-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
7
4
2
5

Solution

There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 21 people needing transportation leaving 21 - 16 = 5 who will have to find other transportation.


2

What is (z2)5?

80% Answer Correctly
5z2
z7
z-3
z10

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(z2)5
z(2 * 5)
z10


3

A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 9 to 2 and the ratio of baseball to basketball cards is 9 to 1, what is the ratio of football to basketball cards?

53% Answer Correctly
81:2
3:1
9:6
7:8

Solution

The ratio of football cards to baseball cards is 9:2 and the ratio of baseball cards to basketball cards is 9:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 81:18 and the ratio of baseball cards to basketball cards as 18:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 81:18, 18:2 which reduces to 81:2.


4

What is \( \frac{28\sqrt{15}}{4\sqrt{3}} \)?

71% Answer Correctly
5 \( \sqrt{7} \)
\(\frac{1}{7}\) \( \sqrt{\frac{1}{5}} \)
7 \( \sqrt{5} \)
\(\frac{1}{7}\) \( \sqrt{5} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{28\sqrt{15}}{4\sqrt{3}} \)
\( \frac{28}{4} \) \( \sqrt{\frac{15}{3}} \)
7 \( \sqrt{5} \)


5

What is -4c3 x 8c2?

75% Answer Correctly
-32c5
4c6
-32c
-32c-1

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-4c3 x 8c2
(-4 x 8)c(3 + 2)
-32c5