ASVAB Arithmetic Reasoning Practice Test 648866 Results

Your Results Global Average
Questions 5 5
Correct 0 3.44
Score 0% 69%

Review

1

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for division

distributive property for multiplication

commutative property for multiplication

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


2

What is the least common multiple of 3 and 7?

73% Answer Correctly
7
12
21
16

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 have in common.


3

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

improper fraction

integer

fraction

mixed number


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


4

How many 16-passenger vans will it take to drive all 30 members of the football team to an away game?

81% Answer Correctly
3 vans
4 vans
6 vans
2 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{30}{16} \) = 1\(\frac{7}{8}\)

So, it will take 1 full vans and one partially full van to transport the entire team making a total of 2 vans.


5

If all of a roofing company's 20 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?

55% Answer Correctly
12
11
8
14

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 20 workers at the company now and that's enough to staff 5 crews so there are \( \frac{20}{5} \) = 4 workers on a crew. 7 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 7 x 4 = 28 total workers to staff the crews during the busy season. The company already employs 20 workers so they need to add 28 - 20 = 8 new staff for the busy season.