| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.44 |
| Score | 0% | 69% |
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for multiplication |
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commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
What is the least common multiple of 3 and 7?
| 7 | |
| 12 | |
| 21 | |
| 16 |
The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 have in common.
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
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integer |
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fraction |
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mixed number |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
How many 16-passenger vans will it take to drive all 30 members of the football team to an away game?
| 3 vans | |
| 4 vans | |
| 6 vans | |
| 2 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{30}{16} \) = 1\(\frac{7}{8}\)
So, it will take 1 full vans and one partially full van to transport the entire team making a total of 2 vans.
If all of a roofing company's 20 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 12 | |
| 11 | |
| 8 | |
| 14 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 20 workers at the company now and that's enough to staff 5 crews so there are \( \frac{20}{5} \) = 4 workers on a crew. 7 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 7 x 4 = 28 total workers to staff the crews during the busy season. The company already employs 20 workers so they need to add 28 - 20 = 8 new staff for the busy season.