| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.36 |
| Score | 0% | 67% |
Simplify \( \sqrt{20} \)
| 3\( \sqrt{10} \) | |
| 2\( \sqrt{5} \) | |
| 5\( \sqrt{10} \) | |
| 7\( \sqrt{10} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{20} \)
\( \sqrt{4 \times 5} \)
\( \sqrt{2^2 \times 5} \)
2\( \sqrt{5} \)
Christine scored 85% on her final exam. If each question was worth 4 points and there were 160 possible points on the exam, how many questions did Christine answer correctly?
| 34 | |
| 35 | |
| 26 | |
| 40 |
Christine scored 85% on the test meaning she earned 85% of the possible points on the test. There were 160 possible points on the test so she earned 160 x 0.85 = 136 points. Each question is worth 4 points so she got \( \frac{136}{4} \) = 34 questions right.
a(b + c) = ab + ac defines which of the following?
commutative property for multiplication |
|
distributive property for multiplication |
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commutative property for division |
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distributive property for division |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
Which of the following is an improper fraction?
\({7 \over 5} \) |
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\(1 {2 \over 5} \) |
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\({2 \over 5} \) |
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\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is \( \sqrt{\frac{36}{81}} \)?
| \(\frac{4}{5}\) | |
| \(\frac{8}{9}\) | |
| \(\frac{2}{3}\) | |
| 1 |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{36}{81}} \)
\( \frac{\sqrt{36}}{\sqrt{81}} \)
\( \frac{\sqrt{6^2}}{\sqrt{9^2}} \)
\(\frac{2}{3}\)