| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.43 |
| Score | 0% | 69% |
Monty loaned Latoya $800 at an annual interest rate of 2%. If no payments are made, what is the total amount owed at the end of the first year?
| $824 | |
| $848 | |
| $864 | |
| $816 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $800
i = 0.02 x $800
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $800 + $16What is 8y4 x 2y2?
| 16y4 | |
| 16y8 | |
| 10y4 | |
| 16y6 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
8y4 x 2y2
(8 x 2)y(4 + 2)
16y6
A circular logo is enlarged to fit the lid of a jar. The new diameter is 35% larger than the original. By what percentage has the area of the logo increased?
| 27\(\frac{1}{2}\)% | |
| 15% | |
| 22\(\frac{1}{2}\)% | |
| 17\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 35% the radius (and, consequently, the total area) increases by \( \frac{35\text{%}}{2} \) = 17\(\frac{1}{2}\)%
What is \( \frac{6\sqrt{40}}{3\sqrt{8}} \)?
| 5 \( \sqrt{\frac{1}{2}} \) | |
| \(\frac{1}{2}\) \( \sqrt{5} \) | |
| 2 \( \sqrt{5} \) | |
| 2 \( \sqrt{\frac{1}{5}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{6\sqrt{40}}{3\sqrt{8}} \)
\( \frac{6}{3} \) \( \sqrt{\frac{40}{8}} \)
2 \( \sqrt{5} \)
Find the average of the following numbers: 15, 13, 16, 12.
| 14 | |
| 18 | |
| 13 | |
| 17 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{15 + 13 + 16 + 12}{4} \) = \( \frac{56}{4} \) = 14