| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 8 | |
| 16 | |
| 14 | |
| 12 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 7 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 7 x 3 = 21 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 21 - 9 = 12 new staff for the busy season.
What is \( \frac{4}{9} \) x \( \frac{4}{7} \)?
| \(\frac{16}{63}\) | |
| \(\frac{4}{63}\) | |
| \(\frac{9}{56}\) | |
| 1\(\frac{7}{9}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{9} \) x \( \frac{4}{7} \) = \( \frac{4 x 4}{9 x 7} \) = \( \frac{16}{63} \) = \(\frac{16}{63}\)
4! = ?
4 x 3 x 2 x 1 |
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5 x 4 x 3 x 2 x 1 |
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3 x 2 x 1 |
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4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
a(b + c) = ab + ac defines which of the following?
distributive property for multiplication |
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commutative property for multiplication |
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commutative property for division |
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distributive property for division |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
What is \( 4 \)\( \sqrt{80} \) - \( 4 \)\( \sqrt{5} \)
| 0\( \sqrt{5} \) | |
| 0\( \sqrt{9} \) | |
| 12\( \sqrt{5} \) | |
| 0\( \sqrt{80} \) |
To subtract these radicals together their radicands must be the same:
4\( \sqrt{80} \) - 4\( \sqrt{5} \)
4\( \sqrt{16 \times 5} \) - 4\( \sqrt{5} \)
4\( \sqrt{4^2 \times 5} \) - 4\( \sqrt{5} \)
(4)(4)\( \sqrt{5} \) - 4\( \sqrt{5} \)
16\( \sqrt{5} \) - 4\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
16\( \sqrt{5} \) - 4\( \sqrt{5} \)