ASVAB Electronics Information Practice Test 265065 Results

Your Results Global Average
Questions 5 5
Correct 0 3.61
Score 0% 72%

Review

1

Using a fuse with a current rating higher than that required by a circuit:

70% Answer Correctly

is required

makes the circuit less safe

makes no difference

is recommended


Solution

A fuse is a type of low resistance resistor that stops current flow in a circuit in response to a larger than intended electric current flow. Using a fuse with a higher current rating than required by a circuit is less safe as it could potentially allow overcurrent and risk a fire or heat-related equipment damage.


2

This circuit component symbol represents a(n):

66% Answer Correctly

transformer

DC source

transistor

AC source


Solution

In contrast to the constant one-way flow of direct current, alternating current changes direction many times each second. Electricity is delivered from power stations to customers as AC because it provides a more efficient way to transport electricity over long distances.


3

Which of the following will help to prevent a short circuit?

74% Answer Correctly

fuse

diode

transistor

resistor


Solution

Fuses are thin wires that melt when the current in a circuit exceeds a preset amount. They help prevent short circuits from damaging circuit components when an unusually large current is applied to the circuit, either through component failure or spikes in applied voltage.


4

An amplifier is most similar in function to which of the following:

65% Answer Correctly

step-down transformer

step-up transformer

capacitor

transistor


Solution

An amplifier is a device that takes a small input signal and creates a larger output signal. This makes it most similar to a step-up transformer which takes a smaller input voltage and creates a larger output voltage.


5 A circuit with a 120-volt power supply is protected by a 20-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?
85% Answer Correctly
2399 W
7200 W
2401.5 W
2400 W

Solution
Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 20A circuit breaker would allow is 120V x 20A = 2400 W.