ASVAB Electronics Information Practice Test 422226 Results

Your Results Global Average
Questions 5 5
Correct 0 3.31
Score 0% 66%

Review

1

Which of the following is a characteristic of batteries connected in parallel?

52% Answer Correctly

the positive terminal of one battery is connected to the negative terminal of the next

total current equals the sum of the individual battery currents

one connection is made between each adjacent battery

total current equals the average of the individual battery currents


Solution

You can multiply the voltage or the current supplied by individual batteries by connecting them together either in series or in parallel. The characteristics of batteries connected in parallel are that total voltage equals the average of the individual battery voltages, total current equals the sum of the individual battery currents, the positive terminal of one battery is connected to the positive terminal of the next, the negative terminal of one battery is connected to the negative terminal of the next, and two connections are made between each adjacent battery.


2

A diode to an electronic circuit is like a _______________ to a city?

67% Answer Correctly

parking lot

highway

traffic light

one-way street


Solution

A diode allows current to pass easily in one direction and blocks current in the other direction.


3 How would you connect 6 [9V 10A] batteries to achieve a combined power output of 9V 60A?
52% Answer Correctly
series-parallel
parallel
orthogonal
series

Solution

Connecting the 6 batteries in series multiplies their voltage while keeping their current the same yielding a 54V 10A configuration. Connecting the 6 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 60A configuration. Using a series-parallel connection, 3 batteries can be connected in series and 3 can be connected in parallel resulting in a 27V 30A configuration.


4 Use Ohm's Law to calculate the value of current in this circuit if voltage is 45 volts and resistance is 10 Ω.
80% Answer Correctly
13.5 A
0.5 A
4.5 A
6.75 A

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for current, I = \( \frac{V}{R} \) = \( \frac{45}{10} \) = 4.5 A


5 Use Ohm's Law to calculate the value of resistance in this circuit if voltage is 75 volts and current is 2.5 amps.
80% Answer Correctly
31.5 Ω
60 Ω
45 Ω
30 Ω

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for resistance, R = \( \frac{V}{I} \) = \( \frac{75}{2.5} \) = 30 Ω