ASVAB Electronics Information Practice Test 53347 Results

Your Results Global Average
Questions 5 5
Correct 0 3.53
Score 0% 71%

Review

1

Alternating current changes __________ many times each second.

72% Answer Correctly

resistance

direction

period

frequency


Solution

In contrast to the constant one-way flow of direct current, alternating current changes direction many times each second. Electricity is delivered from power stations to customers as AC because it provides a more efficient way to transport electricity over long distances.


2

You would measure the amount of current through a circuit with a(n):

69% Answer Correctly

ammeter

potentiometer

voltmeter

battery


Solution

Current is the rate of flow of electrons per unit time and is measured in amperes (A). An ammeter is used to measure the electric current in a circuit.


3

This circuit diagram represents a(n):

65% Answer Correctly

series circuit

rectifier

parallel circuit

series-parallel circuit


Solution

In a parallel circuit, each load occupies a separate parallel path in the circuit and the input voltage is fully applied to each path. Unlike a series circuit where current (I) is the same at all points in the circuit, in a parallel circuit, voltage (V) is the same across each parallel branch of the circuit but current differs in each branch depending on the load (resistance) present.


4

A transistor to an electronic circuit is like a _______________ to a house?

68% Answer Correctly

no trespassing sign

safe

driveway

gate


Solution

A transistor works by allowing a small amount of current applied at the base to control general current flow from collector to emitter through the transistor. A transistor acts as a gate or switch for electronic signals.


5 Use Ohm's Law to calculate the value of current in this circuit if voltage is 850 volts and resistance is 100 Ω.
80% Answer Correctly
4.25 A
9.5 A
10.5 A
8.5 A

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for current, I = \( \frac{V}{R} \) = \( \frac{850}{100} \) = 8.5 A