When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 8c = -4c - 4z - 5 for c in terms of z.
| -1\(\frac{4}{9}\)z + \(\frac{8}{9}\) | |
| -10z - 6 | |
| -\(\frac{4}{7}\)z + \(\frac{9}{14}\) | |
| \(\frac{2}{3}\)z - \(\frac{5}{6}\) |