When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c - 2c = -2c - 4z - 2 for c in terms of z.
| -\(\frac{6}{13}\)z - \(\frac{9}{13}\) | |
| \(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| 3\(\frac{2}{3}\)z + 2\(\frac{1}{3}\) | |
| \(\frac{3}{7}\)z - 1\(\frac{2}{7}\) |