| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
What is 4a3 + 7a3?
| 11a3 | |
| 28a3 | |
| -3a6 | |
| 11a6 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a3 + 7a3 = 11a3
If side x = 11cm, side y = 13cm, and side z = 11cm what is the perimeter of this triangle?
| 31cm | |
| 35cm | |
| 36cm | |
| 19cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 11cm + 13cm + 11cm = 35cm
The endpoints of this line segment are at (-2, 6) and (2, -6). What is the slope-intercept equation for this line?
| y = -3x + 0 | |
| y = 2x - 1 | |
| y = 3x - 3 | |
| y = 3x + 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 0. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, -6) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)Plugging these values into the slope-intercept equation:
y = -3x + 0
If the base of this triangle is 1 and the height is 5, what is the area?
| 97\(\frac{1}{2}\) | |
| 82\(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| 63 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 1 x 5 = \( \frac{5}{2} \) = 2\(\frac{1}{2}\)
Solve for c:
3c + 5 = \( \frac{c}{-6} \)
| 4\(\frac{11}{13}\) | |
| -\(\frac{27}{37}\) | |
| -\(\frac{49}{62}\) | |
| -1\(\frac{11}{19}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
3c + 5 = \( \frac{c}{-6} \)
-6 x (3c + 5) = c
(-6 x 3c) + (-6 x 5) = c
-18c - 30 = c
-18c - 30 - c = 0
-18c - c = 30
-19c = 30
c = \( \frac{30}{-19} \)
c = -1\(\frac{11}{19}\)