ASVAB Math Knowledge Practice Test 1925 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

What is 4a3 + 7a3?

75% Answer Correctly
11a3
28a3
-3a6
11a6

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

4a3 + 7a3 = 11a3


2

If side x = 11cm, side y = 13cm, and side z = 11cm what is the perimeter of this triangle?

84% Answer Correctly
31cm
35cm
36cm
19cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 11cm + 13cm + 11cm = 35cm


3

The endpoints of this line segment are at (-2, 6) and (2, -6). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -3x + 0
y = 2x - 1
y = 3x - 3
y = 3x + 1

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 0. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, -6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)
m = -3

Plugging these values into the slope-intercept equation:

y = -3x + 0


4

If the base of this triangle is 1 and the height is 5, what is the area?

58% Answer Correctly
97\(\frac{1}{2}\)
82\(\frac{1}{2}\)
2\(\frac{1}{2}\)
63

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 1 x 5 = \( \frac{5}{2} \) = 2\(\frac{1}{2}\)


5

Solve for c:
3c + 5 = \( \frac{c}{-6} \)

46% Answer Correctly
4\(\frac{11}{13}\)
-\(\frac{27}{37}\)
-\(\frac{49}{62}\)
-1\(\frac{11}{19}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

3c + 5 = \( \frac{c}{-6} \)
-6 x (3c + 5) = c
(-6 x 3c) + (-6 x 5) = c
-18c - 30 = c
-18c - 30 - c = 0
-18c - c = 30
-19c = 30
c = \( \frac{30}{-19} \)
c = -1\(\frac{11}{19}\)