ASVAB Math Knowledge Practice Test 236106

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3a - 6a = -9a - 6z - 6 for a in terms of z.

-1\(\frac{3}{10}\)z - \(\frac{4}{5}\)
z - \(\frac{1}{2}\)
4z + 6
z - \(\frac{1}{5}\)