| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.75 |
| Score | 0% | 55% |
The dimensions of this cylinder are height (h) = 7 and radius (r) = 4. What is the volume?
| 112π | |
| 486π | |
| 72π | |
| 49π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(42 x 7)
v = 112π
If the base of this triangle is 2 and the height is 4, what is the area?
| 90 | |
| 4 | |
| 15 | |
| 60 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 2 x 4 = \( \frac{8}{2} \) = 4
Solve for c:
c2 - 10c + 24 = 0
| 8 or -5 | |
| 8 or -1 | |
| 4 or 6 | |
| 9 or 4 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
c2 - 10c + 24 = 0
(c - 4)(c - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 4) or (c - 6) must equal zero:
If (c - 4) = 0, c must equal 4
If (c - 6) = 0, c must equal 6
So the solution is that c = 4 or 6
Solve for y:
y2 + 21y + 58 = 5y - 5
| -6 or -9 | |
| -7 or -9 | |
| 1 or -5 | |
| 3 or -7 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 + 21y + 58 = 5y - 5
y2 + 21y + 58 + 5 = 5y
y2 + 21y - 5y + 63 = 0
y2 + 16y + 63 = 0
Next, factor the quadratic equation:
y2 + 16y + 63 = 0
(y + 7)(y + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 7) or (y + 9) must equal zero:
If (y + 7) = 0, y must equal -7
If (y + 9) = 0, y must equal -9
So the solution is that y = -7 or -9
The endpoints of this line segment are at (-2, 0) and (2, 4). What is the slope of this line?
| 2 | |
| -2\(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| 1 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, 4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (0.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)