ASVAB Math Knowledge Practice Test 249265

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 7c = 4c - 2z + 5 for c in terms of z.

\(\frac{13}{18}\)z - \(\frac{7}{18}\)
1\(\frac{5}{6}\)z - 1\(\frac{1}{3}\)
3\(\frac{1}{3}\)z + 2\(\frac{2}{3}\)
4\(\frac{1}{2}\)z - 2\(\frac{1}{2}\)