ASVAB Math Knowledge Practice Test 313978 Results

Your Results Global Average
Questions 5 5
Correct 0 3.77
Score 0% 75%

Review

1

What is 4a - 9a?

80% Answer Correctly
-5a2
-5
-5a
a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

4a - 9a = -5a


2

A coordinate grid is composed of which of the following?

92% Answer Correctly

x-axis

all of these

origin

y-axis


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


3

Simplify 3a x 5b.

86% Answer Correctly
15ab
15\( \frac{b}{a} \)
15\( \frac{a}{b} \)
8ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

3a x 5b = (3 x 5) (a x b) = 15ab


4

The dimensions of this cylinder are height (h) = 7 and radius (r) = 7. What is the surface area?

48% Answer Correctly
28π
168π
12π
196π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(72) + 2π(7 x 7)
sa = 2π(49) + 2π(49)
sa = (2 x 49)π + (2 x 49)π
sa = 98π + 98π
sa = 196π


5

If the area of this square is 9, what is the length of one of the diagonals?

69% Answer Correctly
\( \sqrt{2} \)
3\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)