When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 2c = -5c + z - 3 for c in terms of z.
| -\(\frac{3}{5}\)z + \(\frac{1}{10}\) | |
| -11z - 9 | |
| -z - 6 | |
| -\(\frac{1}{13}\)z - \(\frac{3}{13}\) |