When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3a - 4a = -5a + 6z - 1 for a in terms of z.
| 1\(\frac{3}{7}\)z + 1\(\frac{1}{7}\) | |
| 1\(\frac{1}{4}\)z - \(\frac{1}{8}\) | |
| -\(\frac{1}{9}\)z - \(\frac{5}{9}\) | |
| 15z + 3 |