ASVAB Math Knowledge Practice Test 368792

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -7a + 4a = 6a - z + 2 for a in terms of z.

-1\(\frac{1}{2}\)z - 2\(\frac{1}{2}\)
2\(\frac{2}{5}\)z - \(\frac{1}{5}\)
\(\frac{5}{13}\)z - \(\frac{2}{13}\)
3\(\frac{1}{2}\)z - \(\frac{1}{2}\)