ASVAB Math Knowledge Practice Test 36980

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c + 9c = -4c - 4y - 3 for c in terms of y.

\(\frac{1}{3}\)y - \(\frac{1}{12}\)
6y + 5
2\(\frac{1}{2}\)y + 1\(\frac{1}{2}\)
-1\(\frac{3}{10}\)y - \(\frac{3}{10}\)