ASVAB Math Knowledge Practice Test 374812

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -5c + 8c = 2c - 2z + 2 for c in terms of z.

-\(\frac{3}{4}\)z + 1
1\(\frac{3}{7}\)z - \(\frac{2}{7}\)
-2\(\frac{1}{2}\)z + 2
-2\(\frac{1}{4}\)z - 1\(\frac{1}{4}\)