ASVAB Math Knowledge Practice Test 395292

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b + 4b = 5b - 9z + 3 for b in terms of z.

-5z + 4
6\(\frac{1}{2}\)z - 1\(\frac{1}{2}\)
z - 1\(\frac{1}{2}\)
\(\frac{1}{8}\)z + \(\frac{7}{8}\)