ASVAB Math Knowledge Practice Test 409587 Results

Your Results Global Average
Questions 5 5
Correct 0 2.61
Score 0% 52%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

2(π r2) + 2π rh

4π r2

π r2h

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

The dimensions of this cube are height (h) = 8, length (l) = 1, and width (w) = 5. What is the surface area?

51% Answer Correctly
158
106
188
222

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 1 x 5) + (2 x 5 x 8) + (2 x 1 x 8)
sa = (10) + (80) + (16)
sa = 106


3

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

diameter

circumference

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and isosceles

equilateral, isosceles and right

equilateral and right

isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


5

Solve for z:
z2 - 7z + 6 = 0

58% Answer Correctly
1 or -2
1 or 6
7 or 4
-2 or -2

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z2 - 7z + 6 = 0
(z - 1)(z - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 1) or (z - 6) must equal zero:

If (z - 1) = 0, z must equal 1
If (z - 6) = 0, z must equal 6

So the solution is that z = 1 or 6