ASVAB Math Knowledge Practice Test 451823 Results

Your Results Global Average
Questions 5 5
Correct 0 2.85
Score 0% 57%

Review

1

Solve for c:
-9c + 1 = -5 + 4c

59% Answer Correctly
-\(\frac{1}{2}\)
1\(\frac{1}{3}\)
\(\frac{6}{13}\)
\(\frac{1}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-9c + 1 = -5 + 4c
-9c = -5 + 4c - 1
-9c - 4c = -5 - 1
-13c = -6
c = \( \frac{-6}{-13} \)
c = \(\frac{6}{13}\)


2

The dimensions of this cylinder are height (h) = 2 and radius (r) = 9. What is the surface area?

48% Answer Correctly
120π
54π
198π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 2)
sa = 2π(81) + 2π(18)
sa = (2 x 81)π + (2 x 18)π
sa = 162π + 36π
sa = 198π


3

If c = 9 and x = -4, what is the value of -2c(c - x)?

68% Answer Correctly
-234
-8
450
-70

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-2c(c - x)
-2(9)(9 + 4)
-2(9)(13)
(-18)(13)
-234


4

Simplify (6a)(2ab) + (3a2)(8b).

65% Answer Correctly
88ab2
12ab2
36a2b
-12a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(2ab) + (3a2)(8b)
(6 x 2)(a x a x b) + (3 x 8)(a2 x b)
(12)(a1+1 x b) + (24)(a2b)
12a2b + 24a2b
36a2b


5

Solve for b:
-2b - 3 > \( \frac{b}{-4} \)

44% Answer Correctly
b > \(\frac{1}{2}\)
b > -1\(\frac{5}{7}\)
b > \(\frac{9}{62}\)
b > 1\(\frac{8}{73}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-2b - 3 > \( \frac{b}{-4} \)
-4 x (-2b - 3) > b
(-4 x -2b) + (-4 x -3) > b
8b + 12 > b
8b + 12 - b > 0
8b - b > -12
7b > -12
b > \( \frac{-12}{7} \)
b > -1\(\frac{5}{7}\)