When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3b - 6b = 4b - 2z - 1 for b in terms of z.
| -4z + 1 | |
| -1\(\frac{4}{5}\)z - \(\frac{4}{5}\) | |
| 3\(\frac{1}{3}\)z + 2\(\frac{2}{3}\) | |
| -6z - 1 |