ASVAB Math Knowledge Practice Test 58214

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve a + 2a = 7a - 3z + 8 for a in terms of z.

z - \(\frac{1}{6}\)
\(\frac{3}{14}\)z + \(\frac{3}{7}\)
\(\frac{6}{7}\)z + 1\(\frac{1}{7}\)
\(\frac{5}{6}\)z - 1\(\frac{1}{3}\)