ASVAB Math Knowledge Practice Test 628956

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3a - a = 9a - 5z + 4 for a in terms of z.

\(\frac{4}{5}\)z - 1\(\frac{2}{5}\)
\(\frac{2}{3}\)z - \(\frac{2}{3}\)
-\(\frac{2}{3}\)z + 1
\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)