ASVAB Math Knowledge Practice Test 703306 Results

Your Results Global Average
Questions 5 5
Correct 0 3.29
Score 0% 66%

Review

1

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
5\( \sqrt{2} \)
6\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


2

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and right

equilateral and isosceles

isosceles and right

equilateral, isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


3

Simplify (5a)(9ab) + (5a2)(4b).

65% Answer Correctly
65a2b
-25a2b
25ab2
65ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(9ab) + (5a2)(4b)
(5 x 9)(a x a x b) + (5 x 4)(a2 x b)
(45)(a1+1 x b) + (20)(a2b)
45a2b + 20a2b
65a2b


4

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

trapezoid

quadrilateral

triangle

rhombus


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


5

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

pairs

exponents

division

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)