| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.02 |
| Score | 0% | 60% |
If a = -9 and y = -6, what is the value of 4a(a - y)?
| 108 | |
| -14 | |
| 0 | |
| 54 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
4a(a - y)
4(-9)(-9 + 6)
4(-9)(-3)
(-36)(-3)
108
If a = c = 5, b = d = 2, what is the area of this rectangle?
| 15 | |
| 10 | |
| 36 | |
| 56 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 5 x 2
a = 10
Find the value of c:
7c + x = -7
-4c - x = 8
| -1\(\frac{7}{73}\) | |
| \(\frac{1}{3}\) | |
| -\(\frac{18}{35}\) | |
| -\(\frac{21}{32}\) |
You need to find the value of c so solve the first equation in terms of x:
7c + x = -7
x = -7 - 7c
then substitute the result (-7 - 7c) into the second equation:
-4c - 1(-7 - 7c) = 8
-4c + (-1 x -7) + (-1 x -7c) = 8
-4c + 7 + 7c = 8
-4c + 7c = 8 - 7
3c = 1
c = \( \frac{1}{3} \)
c = \(\frac{1}{3}\)
Solve for a:
a2 - 6a - 7 = 0
| 4 or -8 | |
| -1 or 7 | |
| 2 or -5 | |
| 2 or -1 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
a2 - 6a - 7 = 0
(a + 1)(a - 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a + 1) or (a - 7) must equal zero:
If (a + 1) = 0, a must equal -1
If (a - 7) = 0, a must equal 7
So the solution is that a = -1 or 7
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
|
equilateral and right |
|
equilateral, isosceles and right |
|
equilateral and isosceles |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.