ASVAB Math Knowledge Practice Test 841960 Results

Your Results Global Average
Questions 5 5
Correct 0 3.69
Score 0% 74%

Review

1

Which of the following statements about math operations is incorrect?

71% Answer Correctly

all of these statements are correct

you can subtract monomials that have the same variable and the same exponent

you can add monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


2

Simplify (3a)(9ab) + (3a2)(2b).

66% Answer Correctly
60a2b
21ab2
33a2b
-21a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(9ab) + (3a2)(2b)
(3 x 9)(a x a x b) + (3 x 2)(a2 x b)
(27)(a1+1 x b) + (6)(a2b)
27a2b + 6a2b
33a2b


3

A(n) __________ is two expressions separated by an equal sign.

77% Answer Correctly

expression

formula

equation

problem


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

Simplify 8a x 7b.

86% Answer Correctly
56ab
56a2b2
15ab
56\( \frac{b}{a} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

8a x 7b = (8 x 7) (a x b) = 56ab


5

If the area of this square is 16, what is the length of one of the diagonals?

69% Answer Correctly
4\( \sqrt{2} \)
7\( \sqrt{2} \)
6\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)