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Sample Practice Test Questions
In taxonomy, domains are the broadest classification of life. How many domains are there?
3
The broadest classification of life splits all organisms into three groups called domains. The three domains of life are bacteria, archaea and eukaryota.
What is the large casing that contains the cylinders and many of the internal components of the engine?
engine block
The engine (or cylinder) block is the large casing that contains the cylinders and many of the internal components of the engine.
Solve for \( \frac{5!}{6!} \)
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{6!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6} \)
\( \frac{1}{6} \)
The __________ converts pressure on the brake pedal to hydraulic pressure in the brake lines.
master cylinder
The master (brake) cylinder converts pressure on the brake pedal to hydraulic pressure in the brake lines.
Connecting the 8 batteries in series multiplies their voltage while keeping their current the same yielding a 72V 15A configuration. Connecting the 8 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 120A configuration. Using a series-parallel connection, 4 batteries can be connected in series and 4 can be connected in parallel resulting in a 36V 60A configuration.
If A = 9 ft. and the green box weighs 30 lbs. what is the torque acting on the A side of this lever?
Convert 0C° to F°.
32
To convert from C° to F° use:
\(F° = {9 \over 5}C° + 32\)
\(F° = {9 \over 5}(0) + 32\)
\(F° = 0 + 32 = 32\)
If 15 lbs. of force is applied 8 ft. from the fulcrum at the blue arrow and the green box is 7 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{15 lbs. \times 8 ft.}{7 ft.} \) = \( \frac{120 ft⋅lb}{7 ft.} \) = 17.14 lbs.