When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -b + 6b = -4b + 8z + 7 for b in terms of z.
| 4\(\frac{1}{4}\)z + \(\frac{1}{4}\) | |
| \(\frac{3}{5}\)z + 1\(\frac{3}{5}\) | |
| 1\(\frac{2}{5}\)z + 1 | |
| \(\frac{2}{3}\)z + 2\(\frac{1}{3}\) |