When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -c + 6c = -4c + 8x + 7 for c in terms of x.
4\(\frac{1}{4}\)x + \(\frac{1}{4}\) | |
\(\frac{3}{5}\)x + 1\(\frac{3}{5}\) | |
1\(\frac{2}{5}\)x + 1 | |
\(\frac{2}{3}\)x + 2\(\frac{1}{3}\) |