When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c + 4c = 8c + 6y + 8 for c in terms of y.
| y + 1\(\frac{4}{5}\) | |
| -\(\frac{2}{11}\)y - \(\frac{8}{11}\) | |
| 3\(\frac{1}{5}\)y - 1\(\frac{1}{5}\) | |
| 1\(\frac{2}{5}\)y - \(\frac{2}{5}\) |