Free ASVAB Practice Tests
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Sample Practice Test Questions
Which of the following is used in metal work for shaping metal?
ball peen hammer
Ball peen hammers are most commonly used in automotive repair. They have rounded heads and are used to drive punches and chisels.
The __________ converts pressure on the brake pedal to hydraulic pressure in the brake lines.
master cylinder
The master (brake) cylinder converts pressure on the brake pedal to hydraulic pressure in the brake lines.
Simplify (y + 8)(y + 3)
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 8)(y + 3)
(y x y) + (y x 3) + (8 x y) + (8 x 3)
y2 + 3y + 8y + 24
y2 + 11y + 24
If 15 lbs. of force is applied 8 ft. from the fulcrum at the blue arrow and the green box is 7 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{15 lbs. \times 8 ft.}{7 ft.} \) = \( \frac{120 ft⋅lb}{7 ft.} \) = 17.14 lbs.
What is \( \frac{3}{3} \) - \( \frac{5}{5} \)?
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 5}{3 x 5} \) - \( \frac{5 x 3}{5 x 3} \)
\( \frac{15}{15} \) - \( \frac{15}{15} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{15 - 15}{15} \) = \( \frac{0}{15} \) =
Which of the following determines whether a socket can be used with a particular ratchet?
the drive size
A ratchet (or socket wrench) is a wrench that applies torque in only one direction with a handle that can be moved back and forth without losing contact with the fastener. A ratchet uses variable attachments called sockets which come in a variety of drive sizes based on the size of the opening that attaches to the ratchet. Sockets with the same drive size will vary in the shape (six-point, twelve-point) and size of the nut opening that attaches to the fastener being tightened or loosened. Smaller point sized sockets are stronger and can apply greater torque while larger point sizes allow easier alignment.
What is \( 5 \)\( \sqrt{20} \) - \( 2 \)\( \sqrt{5} \)
To subtract these radicals together their radicands must be the same:
5\( \sqrt{20} \) - 2\( \sqrt{5} \)
5\( \sqrt{4 \times 5} \) - 2\( \sqrt{5} \)
5\( \sqrt{2^2 \times 5} \) - 2\( \sqrt{5} \)
(5)(2)\( \sqrt{5} \) - 2\( \sqrt{5} \)
10\( \sqrt{5} \) - 2\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
10\( \sqrt{5} \) - 2\( \sqrt{5} \)(10 - 2)\( \sqrt{5} \)
8\( \sqrt{5} \)
This circuit component symbol represents a(n):
inductor
An inductor is coiled wire that stores electric energy in the form of magnetic energy and resists changes in the electric current flowing through it. If current is increasing, the inductor produces a voltage that slows the increase and, if current is decreasing, the magnetic energy in the coil opposes the decrease to keep the current flowing longer. In contrast to capacitors, inductors allow DC to pass easily but resist the flow of AC.
The radius of the axle is 3, the radius of the wheel is 4, and the blue box weighs 35 lbs. What is the effort force necessary to balance the load?
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 4 and the output radius (where the resistance is being applied) is 3 for a mechanical advantage of \( \frac{4}{3} \) = 1.33
MA = \( \frac{load}{effort} \) so effort = \( \frac{load}{MA} \) = \( \frac{35 lbs.}{1.33} \) = 26.32 lbs.