ASVAB Arithmetic Reasoning Practice Test 101659 Results

Your Results Global Average
Questions 5 5
Correct 0 3.59
Score 0% 72%

Review

1

7 members of a bridal party need transported to a wedding reception but there are only 2 2-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
7
5
2
3

Solution

There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 7 people needing transportation leaving 7 - 4 = 3 who will have to find other transportation.


2

What is \( \frac{4}{9} \) x \( \frac{2}{7} \)?

72% Answer Correctly
\(\frac{8}{63}\)
\(\frac{2}{15}\)
1\(\frac{1}{7}\)
\(\frac{8}{9}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{2}{7} \) = \( \frac{4 x 2}{9 x 7} \) = \( \frac{8}{63} \) = \(\frac{8}{63}\)


3

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = 7 or a = -7

none of these is correct

a = -7

a = 7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


4

What is 6a2 + 4a2?

66% Answer Correctly
-2a2
-2a-2
10a2
10a-4

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

6a2 + 4a2
(6 + 4)a2
10a2


5

How many 8-passenger vans will it take to drive all 30 members of the football team to an away game?

80% Answer Correctly
11 vans
7 vans
6 vans
4 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{30}{8} \) = 3\(\frac{3}{4}\)

So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.