ASVAB Arithmetic Reasoning Practice Test 102033 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

What is \( \frac{1}{9} \) x \( \frac{3}{6} \)?

72% Answer Correctly
\(\frac{1}{3}\)
\(\frac{8}{35}\)
\(\frac{1}{18}\)
\(\frac{2}{21}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{9} \) x \( \frac{3}{6} \) = \( \frac{1 x 3}{9 x 6} \) = \( \frac{3}{54} \) = \(\frac{1}{18}\)


2

Find the average of the following numbers: 15, 11, 15, 11.

75% Answer Correctly
9
13
10
17

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{15 + 11 + 15 + 11}{4} \) = \( \frac{52}{4} \) = 13


3

What is the distance in miles of a trip that takes 5 hours at an average speed of 50 miles per hour?

87% Answer Correctly
180 miles
250 miles
270 miles
630 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 50mph \times 5h \)
250 miles


4

A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?

62% Answer Correctly
2\(\frac{7}{8}\) cups
1\(\frac{3}{8}\) cups
\(\frac{3}{4}\) cups
\(\frac{7}{8}\) cups

Solution

The amount of flour you need is (3\(\frac{3}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{27}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{23}{8} \) cups
2\(\frac{7}{8}\) cups


5

If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?

47% Answer Correctly
18 m2
2 m2
50 m2
162 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.

Putting these two equations together and solving for width (w):

2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5

Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2