| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.43 |
| Score | 0% | 69% |
What is \( \frac{1}{9} \) x \( \frac{3}{6} \)?
| \(\frac{1}{3}\) | |
| \(\frac{8}{35}\) | |
| \(\frac{1}{18}\) | |
| \(\frac{2}{21}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{9} \) x \( \frac{3}{6} \) = \( \frac{1 x 3}{9 x 6} \) = \( \frac{3}{54} \) = \(\frac{1}{18}\)
Find the average of the following numbers: 15, 11, 15, 11.
| 9 | |
| 13 | |
| 10 | |
| 17 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{15 + 11 + 15 + 11}{4} \) = \( \frac{52}{4} \) = 13
What is the distance in miles of a trip that takes 5 hours at an average speed of 50 miles per hour?
| 180 miles | |
| 250 miles | |
| 270 miles | |
| 630 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 50mph \times 5h \)
250 miles
A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
| 2\(\frac{7}{8}\) cups | |
| 1\(\frac{3}{8}\) cups | |
| \(\frac{3}{4}\) cups | |
| \(\frac{7}{8}\) cups |
The amount of flour you need is (3\(\frac{3}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{27}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{23}{8} \) cups
2\(\frac{7}{8}\) cups
If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?
| 18 m2 | |
| 2 m2 | |
| 50 m2 | |
| 162 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.
Putting these two equations together and solving for width (w):
2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5
Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2