| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
What is \( \frac{5}{8} \) - \( \frac{7}{12} \)?
| \( \frac{3}{24} \) | |
| \( \frac{9}{13} \) | |
| \( \frac{7}{24} \) | |
| \(\frac{1}{24}\) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{5 x 3}{8 x 3} \) - \( \frac{7 x 2}{12 x 2} \)
\( \frac{15}{24} \) - \( \frac{14}{24} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{15 - 14}{24} \) = \( \frac{1}{24} \) = \(\frac{1}{24}\)
9 members of a bridal party need transported to a wedding reception but there are only 2 2-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 4 | |
| 6 | |
| 5 |
There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 9 people needing transportation leaving 9 - 4 = 5 who will have to find other transportation.
How many 1 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 2 | |
| 8 | |
| 6 | |
| 4 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{4 \text{ gallons}}{1 \text{ gallons}} \) = 4
How many 6-passenger vans will it take to drive all 74 members of the football team to an away game?
| 8 vans | |
| 6 vans | |
| 13 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{74}{6} \) = 12\(\frac{1}{3}\)
So, it will take 12 full vans and one partially full van to transport the entire team making a total of 13 vans.
If the ratio of home fans to visiting fans in a crowd is 4:1 and all 46,000 seats in a stadium are filled, how many home fans are in attendance?
| 30,000 | |
| 34,167 | |
| 33,600 | |
| 36,800 |
A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:
46,000 fans x \( \frac{4}{5} \) = \( \frac{184000}{5} \) = 36,800 fans.