First, solve for \( \left|y - 4\right| \):

\( \left|y - 4\right| \) + 5 = 9
\( \left|y - 4\right| \) = 9 - 5
\( \left|y - 4\right| \) = 4

The value inside the absolute value brackets can be either positive or negative so (y - 4) must equal + 4 or -4 for \( \left|y - 4\right| \) to equal 4:

So, y = 0 or y = 8.

The amount of flour you need is (3\(\frac{5}{8}\) - 1) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{29}{8} \) - \( \frac{8}{8} \)) cups
\( \frac{21}{8} \) cups
2\(\frac{5}{8}\) cups

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{5!}{3!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{5 \times 4}{1} \)
\( 5 \times 4 \)
20

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{64}} \)
\( \frac{\sqrt{49}}{\sqrt{64}} \)
\( \frac{\sqrt{7^2}}{\sqrt{8^2}} \)
\(\frac{7}{8}\)

To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 1 gallons so:

cans = \( \frac{5 \text{ gallons}}{1 \text{ gallons}} \) = 5