ASVAB Arithmetic Reasoning Practice Test 108715 Results

Your Results Global Average
Questions 5 5
Correct 0 2.77
Score 0% 55%

Review

1

A bread recipe calls for 3\(\frac{1}{8}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?

62% Answer Correctly
\(\frac{3}{8}\) cups
2\(\frac{5}{8}\) cups
2 cups
\(\frac{1}{2}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{8}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{25}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups


2

Which of these numbers is a factor of 24?

68% Answer Correctly
17
7
15
6

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.


3

What is \( 2 \)\( \sqrt{32} \) + \( 8 \)\( \sqrt{2} \)

35% Answer Correctly
16\( \sqrt{2} \)
10\( \sqrt{2} \)
16\( \sqrt{64} \)
16\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

2\( \sqrt{32} \) + 8\( \sqrt{2} \)
2\( \sqrt{16 \times 2} \) + 8\( \sqrt{2} \)
2\( \sqrt{4^2 \times 2} \) + 8\( \sqrt{2} \)
(2)(4)\( \sqrt{2} \) + 8\( \sqrt{2} \)
8\( \sqrt{2} \) + 8\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

8\( \sqrt{2} \) + 8\( \sqrt{2} \)
(8 + 8)\( \sqrt{2} \)
16\( \sqrt{2} \)


4

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = 7 or a = -7

a = -7

a = 7

none of these is correct


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


5

What is 4\( \sqrt{6} \) x 3\( \sqrt{4} \)?

41% Answer Correctly
7\( \sqrt{24} \)
7\( \sqrt{6} \)
24\( \sqrt{6} \)
7\( \sqrt{4} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

4\( \sqrt{6} \) x 3\( \sqrt{4} \)
(4 x 3)\( \sqrt{6 \times 4} \)
12\( \sqrt{24} \)

Now we need to simplify the radical:

12\( \sqrt{24} \)
12\( \sqrt{6 \times 4} \)
12\( \sqrt{6 \times 2^2} \)
(12)(2)\( \sqrt{6} \)
24\( \sqrt{6} \)