| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
| Score | 0% | 55% |
A bread recipe calls for 3\(\frac{1}{8}\) cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?
| \(\frac{3}{8}\) cups | |
| 2\(\frac{5}{8}\) cups | |
| 2 cups | |
| \(\frac{1}{2}\) cups |
The amount of flour you need is (3\(\frac{1}{8}\) - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{25}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups
Which of these numbers is a factor of 24?
| 17 | |
| 7 | |
| 15 | |
| 6 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.
What is \( 2 \)\( \sqrt{32} \) + \( 8 \)\( \sqrt{2} \)
| 16\( \sqrt{2} \) | |
| 10\( \sqrt{2} \) | |
| 16\( \sqrt{64} \) | |
| 16\( \sqrt{16} \) |
To add these radicals together their radicands must be the same:
2\( \sqrt{32} \) + 8\( \sqrt{2} \)
2\( \sqrt{16 \times 2} \) + 8\( \sqrt{2} \)
2\( \sqrt{4^2 \times 2} \) + 8\( \sqrt{2} \)
(2)(4)\( \sqrt{2} \) + 8\( \sqrt{2} \)
8\( \sqrt{2} \) + 8\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
8\( \sqrt{2} \) + 8\( \sqrt{2} \)If \(\left|a\right| = 7\), which of the following best describes a?
a = 7 or a = -7 |
|
a = -7 |
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a = 7 |
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none of these is correct |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
What is 4\( \sqrt{6} \) x 3\( \sqrt{4} \)?
| 7\( \sqrt{24} \) | |
| 7\( \sqrt{6} \) | |
| 24\( \sqrt{6} \) | |
| 7\( \sqrt{4} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
4\( \sqrt{6} \) x 3\( \sqrt{4} \)
(4 x 3)\( \sqrt{6 \times 4} \)
12\( \sqrt{24} \)
Now we need to simplify the radical:
12\( \sqrt{24} \)
12\( \sqrt{6 \times 4} \)
12\( \sqrt{6 \times 2^2} \)
(12)(2)\( \sqrt{6} \)
24\( \sqrt{6} \)