ASVAB Arithmetic Reasoning Practice Test 109510 Results

Your Results Global Average
Questions 5 5
Correct 0 3.53
Score 0% 71%

Review

1

What is the least common multiple of 4 and 12?

72% Answer Correctly
12
8
18
28

Solution

The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 12 have in common.


2

Convert y-3 to remove the negative exponent.

67% Answer Correctly
\( \frac{3}{y} \)
\( \frac{1}{y^{-3}} \)
\( \frac{-3}{y} \)
\( \frac{1}{y^3} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({a \over 5} \)

\({2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

How many 10-passenger vans will it take to drive all 63 members of the football team to an away game?

81% Answer Correctly
7 vans
9 vans
4 vans
6 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{63}{10} \) = 6\(\frac{3}{10}\)

So, it will take 6 full vans and one partially full van to transport the entire team making a total of 7 vans.


5

A bread recipe calls for 3\(\frac{1}{2}\) cups of flour. If you only have 1\(\frac{1}{2}\) cups, how much more flour is needed?

62% Answer Correctly
1\(\frac{5}{8}\) cups
\(\frac{7}{8}\) cups
2 cups
\(\frac{3}{8}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{2}\) - 1\(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{28}{8} \) - \( \frac{12}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups