| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.55 |
| Score | 0% | 71% |
What is the next number in this sequence: 1, 3, 5, 7, 9, __________ ?
| 19 | |
| 10 | |
| 11 | |
| 17 |
The equation for this sequence is:
an = an-1 + 2
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2
a6 = 9 + 2
a6 = 11
What is \( \frac{6z^6}{7z^4} \)?
| 1\(\frac{1}{6}\)z10 | |
| \(\frac{6}{7}\)z2 | |
| \(\frac{6}{7}\)z\(\frac{2}{3}\) | |
| 1\(\frac{1}{6}\)z2 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{6z^6}{7z^4} \)
\( \frac{6}{7} \) z(6 - 4)
\(\frac{6}{7}\)z2
Which of these numbers is a factor of 32?
| 6 | |
| 11 | |
| 29 | |
| 1 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.
What is \( \frac{2}{6} \) x \( \frac{1}{6} \)?
| \(\frac{1}{27}\) | |
| \(\frac{1}{14}\) | |
| \(\frac{4}{15}\) | |
| \(\frac{1}{18}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{6} \) x \( \frac{1}{6} \) = \( \frac{2 x 1}{6 x 6} \) = \( \frac{2}{36} \) = \(\frac{1}{18}\)
In a class of 15 students, 7 are taking German and 6 are taking Spanish. Of the students studying German or Spanish, 4 are taking both courses. How many students are not enrolled in either course?
| 15 | |
| 6 | |
| 12 | |
| 13 |
The number of students taking German or Spanish is 7 + 6 = 13. Of that group of 13, 4 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 13 - 4 = 9 who are taking at least one language. 15 - 9 = 6 students who are not taking either language.