ASVAB Arithmetic Reasoning Practice Test 109995 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

What is \( 6 \)\( \sqrt{125} \) + \( 7 \)\( \sqrt{5} \)

35% Answer Correctly
37\( \sqrt{5} \)
13\( \sqrt{125} \)
42\( \sqrt{25} \)
13\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

6\( \sqrt{125} \) + 7\( \sqrt{5} \)
6\( \sqrt{25 \times 5} \) + 7\( \sqrt{5} \)
6\( \sqrt{5^2 \times 5} \) + 7\( \sqrt{5} \)
(6)(5)\( \sqrt{5} \) + 7\( \sqrt{5} \)
30\( \sqrt{5} \) + 7\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

30\( \sqrt{5} \) + 7\( \sqrt{5} \)
(30 + 7)\( \sqrt{5} \)
37\( \sqrt{5} \)


2

12 members of a bridal party need transported to a wedding reception but there are only 2 4-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
9
4
1
3

Solution

There are 2 4-passenger taxis available so that's 2 x 4 = 8 total seats. There are 12 people needing transportation leaving 12 - 8 = 4 who will have to find other transportation.


3

In a class of 25 students, 13 are taking German and 6 are taking Spanish. Of the students studying German or Spanish, 6 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
14
12
19
18

Solution

The number of students taking German or Spanish is 13 + 6 = 19. Of that group of 19, 6 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 19 - 6 = 13 who are taking at least one language. 25 - 13 = 12 students who are not taking either language.


4

What is the next number in this sequence: 1, 5, 9, 13, 17, __________ ?

92% Answer Correctly
21
13
22
30

Solution

The equation for this sequence is:

an = an-1 + 4

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 4
a6 = 17 + 4
a6 = 21


5

If a mayor is elected with 79% of the votes cast and 61% of a town's 28,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
13,493
10,248
9,394
14,860

Solution

If 61% of the town's 28,000 voters cast ballots the number of votes cast is:

(\( \frac{61}{100} \)) x 28,000 = \( \frac{1,708,000}{100} \) = 17,080

The mayor got 79% of the votes cast which is:

(\( \frac{79}{100} \)) x 17,080 = \( \frac{1,349,320}{100} \) = 13,493 votes.