| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
A circular logo is enlarged to fit the lid of a jar. The new diameter is 70% larger than the original. By what percentage has the area of the logo increased?
| 37\(\frac{1}{2}\)% | |
| 35% | |
| 27\(\frac{1}{2}\)% | |
| 25% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 70% the radius (and, consequently, the total area) increases by \( \frac{70\text{%}}{2} \) = 35%
Which of the following is a mixed number?
\({7 \over 5} \) |
|
\({5 \over 7} \) |
|
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is \( \frac{1}{8} \) ÷ \( \frac{2}{7} \)?
| \(\frac{1}{5}\) | |
| \(\frac{7}{16}\) | |
| \(\frac{7}{8}\) | |
| 3\(\frac{1}{2}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{1}{8} \) ÷ \( \frac{2}{7} \) = \( \frac{1}{8} \) x \( \frac{7}{2} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{8} \) x \( \frac{7}{2} \) = \( \frac{1 x 7}{8 x 2} \) = \( \frac{7}{16} \) = \(\frac{7}{16}\)
What is \( \frac{4}{9} \) - \( \frac{3}{15} \)?
| \( \frac{1}{45} \) | |
| \( \frac{9}{45} \) | |
| 1 \( \frac{3}{45} \) | |
| \(\frac{11}{45}\) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 5}{9 x 5} \) - \( \frac{3 x 3}{15 x 3} \)
\( \frac{20}{45} \) - \( \frac{9}{45} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{20 - 9}{45} \) = \( \frac{11}{45} \) = \(\frac{11}{45}\)
What is -4c7 x 8c2?
| -32c9 | |
| -32c-5 | |
| -32c5 | |
| 4c2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-4c7 x 8c2
(-4 x 8)c(7 + 2)
-32c9