| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
Simplify \( \sqrt{12} \)
| 9\( \sqrt{6} \) | |
| 4\( \sqrt{6} \) | |
| 2\( \sqrt{3} \) | |
| 6\( \sqrt{3} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{12} \)
\( \sqrt{4 \times 3} \)
\( \sqrt{2^2 \times 3} \)
2\( \sqrt{3} \)
A machine in a factory has an error rate of 8 parts per 100. The machine normally runs 24 hours a day and produces 10 parts per hour. Yesterday the machine was shut down for 9 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 165.4 | |
| 138.2 | |
| 86.4 | |
| 138 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{8}{100} \) x 10 = \( \frac{8 \times 10}{100} \) = \( \frac{80}{100} \) = 0.8 errors per hour
So, in an average hour, the machine will produce 10 - 0.8 = 9.2 error free parts.
The machine ran for 24 - 9 = 15 hours yesterday so you would expect that 15 x 9.2 = 138 error free parts were produced yesterday.
What is \( \frac{12\sqrt{6}}{6\sqrt{3}} \)?
| 2 \( \sqrt{\frac{1}{2}} \) | |
| \(\frac{1}{2}\) \( \sqrt{2} \) | |
| 2 \( \sqrt{2} \) | |
| \(\frac{1}{2}\) \( \sqrt{\frac{1}{2}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{12\sqrt{6}}{6\sqrt{3}} \)
\( \frac{12}{6} \) \( \sqrt{\frac{6}{3}} \)
2 \( \sqrt{2} \)
If the ratio of home fans to visiting fans in a crowd is 4:1 and all 35,000 seats in a stadium are filled, how many home fans are in attendance?
| 31,333 | |
| 33,333 | |
| 25,833 | |
| 28,000 |
A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:
35,000 fans x \( \frac{4}{5} \) = \( \frac{140000}{5} \) = 28,000 fans.
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 46 | |
| 49 | |
| 55 | |
| 43 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46